本帖最后由 Kakashi_8 于 2015-7-16 14:02 编辑
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Question:6 Which of the following standards may be violated when investment advisors cover their own trading errors with compensating trades? A) 3 i3 x7 Y1 k2 S4 q: C! r& H7 g
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0 F) O7 {' O+ Y- t( t0 M5 G9 v/ a | Disclosure of Conflicts to Clients and Prospects. 9 @: ~; ^' U3 S# s3 Z7 V" o
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| Reasonable Basis and Representations.
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( i7 c2 }9 q% g% U8 H- M! J5 Y& [ | Independence and Objectivity.& C5 e- A: d5 g5 s; s) H
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Question:7 Which of the following is one of the four requirements for meeting fiduciary obligations with regard to soft dollar arrangements? Commissions: A)
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| paid must be minimized. & M" n) c x. [- U) a6 k% ~
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| B)
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/ u% ?# {$ Y4 Q, ]1 J3 i | cannot be greater than normal unless the trades being placed are in compensation for a trading error.
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| paid must be reasonable in relation to the research and execution services provided.
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| paid must be held in escrow for the benefit of the client.
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Question:8 Which of the following statements regarding heteroskedasticity is FALSE? A) ) @, _6 B( X' _3 {, x4 a6 `, H
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| The assumption of linear regression is that the residuals are heteroskedastic.
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| Heteroskedasticity may occur in cross-section or time-series analyses.
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! B6 R/ w( H/ ?. T6 |+ Q | Heteroskedasticity results in an estimated variance that is too large and, therefore, affects statistical inference. % R6 m, A# P) f$ x
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| D)
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8 U0 E# @1 N7 L$ v* X | Conditional heteroskedasticity is the case in which the residuals are correlated with the values of the independent variables. ) t6 \4 q8 |) U+ u7 n$ H+ @
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Question:9 Given: Y = 2.83 + 1.5X What is the predicted value of the dependent variable when the value of an independent variable equals 2? A)
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| 2.83
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Question:10 The variance of 100 daily stock returns for Stock A is 0.0078. The variance of 90 daily stock returns for Stock B is 0.0083. What are the hypotheses to test whether these variances are different from one another? A) ; K; [1 L4 x- X
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| H0: σA2 = σB2 versus Ha: σA2 ≠ σB2.
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0 q, j' \( R+ z5 ?& }( ]3 L3 b; C | H0: σA2 = σ02 versus Ha: σA2 ≠ σ02.
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| H0: σA2 ≠ σB2 versus Ha: σA2 = σB2. ' G/ R. v. h( V+ @% Y# P
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| H0: σA2 > σ02 versus Ha: σA2 < σ02. | : \1 I8 i5 h+ Y' u, X5 _! f
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